How to mount an LED 1000 LM Lumen 20W ENERGY SAVING POWER lamp in a circuit?
I have only took 20W. Let me know if there is something other than a transformer and two wires to light ..?
If it is then Lumen 20W for 1000 is 50 lumens per watt – about the same as lamps Fluorescent (50-100lm / W). The first link shows a limited type of data found, but note the comments in the heat sink issues. The second link is a data sheet, showing a guy who needs 12-15V @ up to 1.4 A. The biggest problem is the temperature. Surprisingly there is no thermal resistance specification. However, the TJMax (maximum junction temperature) is 120C, which allows not want it so high, if the environment is 50 ° C and Tj is 100C, which means place 50C is permissible, and that means an overall thermal resistance of 1 degree C / W, including what the law is binding. A heat sink with 1C / W itself is a large multi-fin thing about 150 x 150 x 50 mm, so it needs something like the LED with a fan to run at full power. The connection cables are also apparently sink heat (thermal) connections, so you need to devise a way to divide and isolate the heat sink, so that the electrical connections can be made while Heat is also done away. The heat sink is close to boiling water without a fan, so no plastic pieces around. A fan is essential, less than the power (current) is less than the maximum power .. The driver circuit: This will be a constant current source that provides> 14V DC, vacuum, with current controlled and limited to 1.4 A or less, preferably adjustable. The voltage is pulled down to the LED voltage when connected. It is no doubt transformer or normal wall adapter that produces a constant voltage. You will need a special device. I did some units Omron (Farnell), but> $ 100 and up to 24 V so not sure whether it would be appropriate. However, this is an indication of the price. It would be possible to use a constant voltage of 24V x 2A (maximum of 1.4 A) supply with a series resistance as ballast. This resistance is calculated using Ohm's law as (24V-12.8V) / 1.4 A = 8 ohms to 8.2 ohms resistance To use the standard value. The power of resistance would be V x I for some 16W. At least a size 25 W resistor is needed to not get too hot. This method is wasteful, but it will work so you can see the heat that gets them all. An old type DC power supply for a laptop could be adapted If this resistance is recalculated for the actual voiltages (could be 18V) A source of truth for this can be a dimmer switch inductive ballast so that ranging from 24 V (derived from the network) and designed as a current regulator.
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